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Ñòóäåíòàì > Êóðñîâûå > Ðàñ÷åò ðàäèîðåëåéíîé ëèíèè ñâÿçè ïðÿìîé âèäèìîñòè

Ðàñ÷åò ðàäèîðåëåéíîé ëèíèè ñâÿçè ïðÿìîé âèäèìîñòè

Ñòðàíèöà: 3/4

                ãäå   l = r/R0 = 39/39 = 1 ;               a = y/H0 = 1                      (4.19)

                               m =  *  = 0,79

 

Èç ãðàôèêà Ë1 ðèñ. 1.5 îïðåäåëÿåì ìíîæèòåëü îñëàáëåíèÿ V0 ïðè Í(0)=0

 

                                                 V0 = -18 äÁ

 

Ðàññ÷èòàåì çíà÷åíèå îòíîñèòåëüíîãî ïðîñâåòà p(g0) , ïðè êîòîðîì íàñòóïàåò

ãëóáîêîå çàìèðàíèå ñèãíàëà, âûçâàííîå ýêðàíèðîâêîé ïðåïÿòñòâèåì ìèíèìàëüíîé

çîíû Ôðåíåëÿ.

                                             p(g0) = (V0 - Vmin)/V0                                      (4.20)

                                    p(g0) = [ -18 - (-33,67)]/-18 = -0,87

 

Ðàññ÷èòàåì ïàðàìåòð Y

 

                                           Y = 2,31 * A[p(g) - p(g0)]                                 (4.21)

                          ãäå           À = 1/s *                            (4.22)

                       A = 1/10,5*10-8 *  = 0,983

                                 y = 2,31 * 0,983 * [1,44 - (-0,87)] = 5,3

 

Èç ãðàôèêà Ë1 ðèñ. 1.6 îïðåäåëÿåì çíà÷åíèå T0(Vmin)

 

                                                    T0(Vmin) » 0 %

 

Ðàñ÷åò âåëè÷èíû Tèíò(Vmin) íà ïåðåñå÷åííîì ïðîëåòå îïðåäåëÿåòñÿ òîëüêî çàìèðàíèÿìè èç-çà îòðàæåíèé ðàäèîâîëí îò ñëîèñòûõ íåîäíîðîäíîñòåé òðîïîñôåðû.

                                         Tèíò(Vmin) = Vmin2 * T(De)                                   (4.23)

                        ãäå           Vmin - â îòíîñèòåëüíûõ åäèíèöàõ

                                                  Vmin = -33,67 äÁ

                                                  Vmin = 4,3 * 10-4

                                       T(De) = 4,1*10-4*x*R0*                                (4.24)

 

 

                  ãäå       x = 1    äëÿ ñóõîïóòíûõ òðàññ

                               R0 - â êèëîìåòðàõ

                               f0 - â ãèãàãåðöàõ

                                    T(De) = 4,1 * 10-4 * 392 * = 1,63 %

                                   Tèíò(Vmin) = (4,3 * 10-4)2 * 1,63 = 3 * 10-7 %

 

Ïðåäåëüíî äîïóñòèìàÿ èíòåíñèâíîñòü äîæäÿ J äëÿ äàííîãî ïðîëåòà îïðåäåëÿåì

èç ãðàôèêà Ë1 ðèñ. 1.9 ïî èçâåñòíîìó çíà÷åíèþ Vmin = -33,67 äÁ

 

                                                          J > 190 ìì/÷

 

        Ïî íàéäåííîé èíòåíñèâíîñòè äîæäÿ îïðåäåëÿåì Òä(Vmin) ïî ãðàôèêó

Ë1 ðèñ. 1.10

                                                     Òä(Vmin) » 0,00014 %

 

Ñóììàðíàÿ âåðîÿòíîñòü óõóäøåíèÿ êà÷åñòâà ïî ôîðìóëå 4.14

 

                      Tïð(Vmin) = 0 + 3*10-7 + 14*10-5 = 1,4 * 10-4 %

 

4.4.  Ðàñ÷åò óñòîé÷èâîñòè ñâÿçè íà ÐÐË

 

         Ïîñëå ðàñ÷åòà äëÿ êàæäîãî ïðîëåòà ÐÐË âåëè÷èí Ò0(Vmin), Tèíò(Vmin), Tä(Vmin)

ðàññ÷èòûâàþò ñóììàðíûé ïðîöåíò âðåìåíè óõóäøåíèÿ êà÷åñòâà ñâÿçè äëÿ âñåé ÐÐË:

                    Tå(Vmin) = T0i(Vmin) + Òèíò(Vmin) + Täi(Vmin)       (4.25)

       ãäå        n - ÷èñëî ïðîëåòîâ ïðîåêòèðóåìîé ÐÐË

                                                           n = 18

                  Tå(Vmin) = 18 * 0 + 18 * 3 * 10-7 + 18 * 14 * 10-5 = 2,5 * 10-3 %

 

Äîïóñòèìûé ïðîöåíò âðåìåíè óõóäøåíèÿ êà÷åñòâà ñâÿçè äëÿ âñåé ÐÐË:

 

                                        Täîï(Vmin) = 0,1 % * L/2500                                (4.26)

                   ãäå        L - äëèíà òðàññû       L = 560 êì

                                    Òäîï(Vmin) = 0,1 * 560/2500 = 22,4 * 10-3

                                                 Tå(Vmin) < Täîï(Vmin)

                                                2,5 * 10-3 < 22,4 * 10-3

 

Òàêèì îáðàçîì ñóììàðíûé ïðîöåíò âðåìåíè óõóäøåíèÿ êà÷åñòâà ñâÿçè äëÿ âñåé ÐÐË íå ïðåâûøàåò äîïóñòèìîãî ïðîöåíòà.

 

 

5.    ÐÀÑ×ÅÒ ÎÆÈÄÀÅÌÎÉ ÌÎÙÍÎÑÒÈ ØÓÌΠÍÀ ÂÛÕÎÄÅ ÊÀÍÀËÀ

     ÒÎÍÀËÜÍÎÉ ×ÀÑÒÎÒÛ È ÎÒÍÎØÅÍÈÅ ÑÈÃÍÀË - ØÓÌ ÍÀ ÂÛÕÎÄÅ

                                                         ÒÂ ÊÀÍÀËÀ

 

5.1.  Ðàñ÷åò ìîùíîñòè øóìîâ íà âûõîäå ÒÔ êàíàëà

 

         Ïðè ðåàëüíîì ïðîåêòèðîâàíèè ÐÐË ðàññ÷èòûâàþò òîëüêî Ðò(80) äëÿ

âåðõíåãî ÒÔ êàíàëà:

 

                                 10 lg Pò(80) = 90 - Êòô - Lïîñò - V2(80)                           (5.1)

              ãäå         Êòô = 153,8 äÁ     (òàáë. 1.1)

                            Lïîñò = -70,13 äÁ    èç 4.11

                            V2(80) = -3 äÁ    (Ë1 òàáë. 1.5)

                            10 lgPò(80) = 90 - 153,8 + 70,13 + 3 = 9,33

                             Pò(80) = 8,57 ïÂò

 

Ìîùíîñòü øóìà èç-çà îòðàæåíèé â ÀÔÒ :

 

                                             ÐÀÔÒ = ÐÀÔÒ1 + ÐÀÔÒ2                                          (5.2)

                 ãäå   ÐÀÔÒ1 - ìîùíîñòü øóìà, îáóñëîâëåííàÿ âíóòðåííèì âîëíîâîäîì

 

                                    ÐÀÔÒ1 = 0,8 ïÂò  (Ë2  ðèñ. 1.36)

 

                          ÐÀÔÒ2 - ìîùíîñòü øóìà, îáóñëîâëåííàÿ âíåøíèì âîëíîâîäîì,

íå çàâèñèò îò äëèíû ýòîãî âîëíîâîäà è ìîæåò áûòü ïðèíÿòà ðàâíîé 5,8 ïÂò

 

                                             ÐÀÔÒ = 0,8 + 5 = 5,8 ïÂò

 

Ñóììàðíàÿ ìîùíîñòü øóìà íà âûõîäå ÒÔ êàíàëà (â ÒÎÍÓ) â êîíöå ïðîåêòèðóåìîé ÐÐË :

 

                        Ðøå = Ðòi(80) + ÐÂ×i + ÐÀÔÒ + Ðãðk          (5.3)

         ãäå   n - ÷èñëî ïðîìåæóòî÷íûõ ñòàíöèé íà ïðîåêòèðóåìîé ÐÐË   n = 13;

                 m - ÷èñëî óçëîâûõ ñòàíöèé  m = 4;

                  Ðãð - íåëèíåéíûé øóì â âåðõíåì ÒÔ êàíàëå çà ñ÷åò ãðóïïîâîãî

                            òðàêòà Ðãð = 20 ïÂò0   (òàáë. 1.1)

                  ÐÂ× - íåëèíåéíûé øóì â âåðõíåì ÒÔ êàíàëå çà ñ÷åò Â× êàíàëà

                                      ÐÂ× = 25 ïÂò0   (òàáë. 1.1)

                  Ðøå = 111,41 + 325 + 150,8 + 80 = 667,2 ïÂò

 

Ñóììàðíàÿ ìîùíîñòü øóìà, ðàññ÷èòàííàÿ ïî ôîðìóëå 5.3 ñðàâíèì ñ äîïóñòèìîé,

îïðåäåëÿåìîé ðåêîìåíäàöèÿìè ÌÊÊÐ:

 

                                               Ðø äîï(80) = 3L + 200                                       (5.4)

              ãäå      L - äëèíà ÐÐË, êì            280 < L < 840

 

                                   Ðø äîï(80) = 3*560 + 200 = 1880 ïÂò

 

Ðàññ÷èòàííàÿ ìîùíîñòü íå ïðåâûøàåò äîïóñòèìîé

 

                                             667,2 ïÂò < 1870 ïÂò

 

5.2   Ðàñ÷åò ñèãíàë-øóì íà âûõîäå Ò êàíàëà

 

              êàíàëå ïåðåäà÷è Ò èçîáðàæåíèÿ ñóììàðíîå îòíîøåíèå øóì-ñèãíàë:

 

             (Uø/Uðñ)2å80% = (Uø/Uðñ)280% + n(Uø/Uðñ)ãåò + m(Uø/Uðñ)ìîä     (5.5)

          ãäå     n - ÷èñëî ïðîëåòîâ íà ÐÐË    n = 18

                    m - ÷èñëî ó÷àñòêîâ                 m = 5

 

                               10lg(Uø/Uðñ)280% = -(KÒÂ + Lïîñò + V(80))                       (5.6)

          ãäå    V(80) = -3 äÁ    (Ë1 òàáë. 1.5)

                    ÊÒ = 152,8 äÁ   (òàáë.1.1)

                    Lïîñò = -70,13 äÁ  èç ôîðìóëû 4.11

 

                         10lg(Uø/Uðñ)280% = -(152,8 - 70,13 - 3) = -79,67 äÁ

                                           (Uø/Uðñ)280% = 1,1*10-8                                          (5.7)

                                        (Uø/Uðñ)ãåò = 0,07/700 = 10-4                                    (5.8)

                                        (Uø/Uðñ)ìîä = 0,14/700 = 2*10-4                               (5.9)

      ãäå         Uø ãåò = 0,07 ì       (òàáë.1.1)

                    Uø ìîä = 0,14 ì      (òàáë. 1.1)

                    Uðñ = 700 ì            (òàáë. 1.1)